Optimal. Leaf size=89 \[ \frac{a^2 A c^2 \sin (e+f x) \cos ^3(e+f x)}{4 f}+\frac{3 a^2 A c^2 \sin (e+f x) \cos (e+f x)}{8 f}+\frac{3}{8} a^2 A c^2 x-\frac{a^2 B c^2 \cos ^5(e+f x)}{5 f} \]
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Rubi [A] time = 0.136876, antiderivative size = 89, normalized size of antiderivative = 1., number of steps used = 5, number of rules used = 4, integrand size = 36, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.111, Rules used = {2967, 2669, 2635, 8} \[ \frac{a^2 A c^2 \sin (e+f x) \cos ^3(e+f x)}{4 f}+\frac{3 a^2 A c^2 \sin (e+f x) \cos (e+f x)}{8 f}+\frac{3}{8} a^2 A c^2 x-\frac{a^2 B c^2 \cos ^5(e+f x)}{5 f} \]
Antiderivative was successfully verified.
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Rule 2967
Rule 2669
Rule 2635
Rule 8
Rubi steps
\begin{align*} \int (a+a \sin (e+f x))^2 (A+B \sin (e+f x)) (c-c \sin (e+f x))^2 \, dx &=\left (a^2 c^2\right ) \int \cos ^4(e+f x) (A+B \sin (e+f x)) \, dx\\ &=-\frac{a^2 B c^2 \cos ^5(e+f x)}{5 f}+\left (a^2 A c^2\right ) \int \cos ^4(e+f x) \, dx\\ &=-\frac{a^2 B c^2 \cos ^5(e+f x)}{5 f}+\frac{a^2 A c^2 \cos ^3(e+f x) \sin (e+f x)}{4 f}+\frac{1}{4} \left (3 a^2 A c^2\right ) \int \cos ^2(e+f x) \, dx\\ &=-\frac{a^2 B c^2 \cos ^5(e+f x)}{5 f}+\frac{3 a^2 A c^2 \cos (e+f x) \sin (e+f x)}{8 f}+\frac{a^2 A c^2 \cos ^3(e+f x) \sin (e+f x)}{4 f}+\frac{1}{8} \left (3 a^2 A c^2\right ) \int 1 \, dx\\ &=\frac{3}{8} a^2 A c^2 x-\frac{a^2 B c^2 \cos ^5(e+f x)}{5 f}+\frac{3 a^2 A c^2 \cos (e+f x) \sin (e+f x)}{8 f}+\frac{a^2 A c^2 \cos ^3(e+f x) \sin (e+f x)}{4 f}\\ \end{align*}
Mathematica [A] time = 0.143001, size = 54, normalized size = 0.61 \[ \frac{a^2 c^2 \left (5 A (12 (e+f x)+8 \sin (2 (e+f x))+\sin (4 (e+f x)))-32 B \cos ^5(e+f x)\right )}{160 f} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.026, size = 166, normalized size = 1.9 \begin{align*}{\frac{1}{f} \left ( -{\frac{B{a}^{2}{c}^{2}\cos \left ( fx+e \right ) }{5} \left ({\frac{8}{3}}+ \left ( \sin \left ( fx+e \right ) \right ) ^{4}+{\frac{4\, \left ( \sin \left ( fx+e \right ) \right ) ^{2}}{3}} \right ) }+A{a}^{2}{c}^{2} \left ( -{\frac{\cos \left ( fx+e \right ) }{4} \left ( \left ( \sin \left ( fx+e \right ) \right ) ^{3}+{\frac{3\,\sin \left ( fx+e \right ) }{2}} \right ) }+{\frac{3\,fx}{8}}+{\frac{3\,e}{8}} \right ) +{\frac{2\,B{a}^{2}{c}^{2} \left ( 2+ \left ( \sin \left ( fx+e \right ) \right ) ^{2} \right ) \cos \left ( fx+e \right ) }{3}}-2\,A{a}^{2}{c}^{2} \left ( -1/2\,\sin \left ( fx+e \right ) \cos \left ( fx+e \right ) +1/2\,fx+e/2 \right ) -B{a}^{2}{c}^{2}\cos \left ( fx+e \right ) +A{a}^{2}{c}^{2} \left ( fx+e \right ) \right ) } \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [B] time = 0.96787, size = 221, normalized size = 2.48 \begin{align*} \frac{15 \,{\left (12 \, f x + 12 \, e + \sin \left (4 \, f x + 4 \, e\right ) - 8 \, \sin \left (2 \, f x + 2 \, e\right )\right )} A a^{2} c^{2} - 240 \,{\left (2 \, f x + 2 \, e - \sin \left (2 \, f x + 2 \, e\right )\right )} A a^{2} c^{2} + 480 \,{\left (f x + e\right )} A a^{2} c^{2} - 32 \,{\left (3 \, \cos \left (f x + e\right )^{5} - 10 \, \cos \left (f x + e\right )^{3} + 15 \, \cos \left (f x + e\right )\right )} B a^{2} c^{2} - 320 \,{\left (\cos \left (f x + e\right )^{3} - 3 \, \cos \left (f x + e\right )\right )} B a^{2} c^{2} - 480 \, B a^{2} c^{2} \cos \left (f x + e\right )}{480 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 1.46277, size = 176, normalized size = 1.98 \begin{align*} -\frac{8 \, B a^{2} c^{2} \cos \left (f x + e\right )^{5} - 15 \, A a^{2} c^{2} f x - 5 \,{\left (2 \, A a^{2} c^{2} \cos \left (f x + e\right )^{3} + 3 \, A a^{2} c^{2} \cos \left (f x + e\right )\right )} \sin \left (f x + e\right )}{40 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [A] time = 4.94064, size = 372, normalized size = 4.18 \begin{align*} \begin{cases} \frac{3 A a^{2} c^{2} x \sin ^{4}{\left (e + f x \right )}}{8} + \frac{3 A a^{2} c^{2} x \sin ^{2}{\left (e + f x \right )} \cos ^{2}{\left (e + f x \right )}}{4} - A a^{2} c^{2} x \sin ^{2}{\left (e + f x \right )} + \frac{3 A a^{2} c^{2} x \cos ^{4}{\left (e + f x \right )}}{8} - A a^{2} c^{2} x \cos ^{2}{\left (e + f x \right )} + A a^{2} c^{2} x - \frac{5 A a^{2} c^{2} \sin ^{3}{\left (e + f x \right )} \cos{\left (e + f x \right )}}{8 f} - \frac{3 A a^{2} c^{2} \sin{\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{8 f} + \frac{A a^{2} c^{2} \sin{\left (e + f x \right )} \cos{\left (e + f x \right )}}{f} - \frac{B a^{2} c^{2} \sin ^{4}{\left (e + f x \right )} \cos{\left (e + f x \right )}}{f} - \frac{4 B a^{2} c^{2} \sin ^{2}{\left (e + f x \right )} \cos ^{3}{\left (e + f x \right )}}{3 f} + \frac{2 B a^{2} c^{2} \sin ^{2}{\left (e + f x \right )} \cos{\left (e + f x \right )}}{f} - \frac{8 B a^{2} c^{2} \cos ^{5}{\left (e + f x \right )}}{15 f} + \frac{4 B a^{2} c^{2} \cos ^{3}{\left (e + f x \right )}}{3 f} - \frac{B a^{2} c^{2} \cos{\left (e + f x \right )}}{f} & \text{for}\: f \neq 0 \\x \left (A + B \sin{\left (e \right )}\right ) \left (a \sin{\left (e \right )} + a\right )^{2} \left (- c \sin{\left (e \right )} + c\right )^{2} & \text{otherwise} \end{cases} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.21036, size = 159, normalized size = 1.79 \begin{align*} \frac{3}{8} \, A a^{2} c^{2} x - \frac{B a^{2} c^{2} \cos \left (5 \, f x + 5 \, e\right )}{80 \, f} - \frac{B a^{2} c^{2} \cos \left (3 \, f x + 3 \, e\right )}{16 \, f} - \frac{B a^{2} c^{2} \cos \left (f x + e\right )}{8 \, f} + \frac{A a^{2} c^{2} \sin \left (4 \, f x + 4 \, e\right )}{32 \, f} + \frac{A a^{2} c^{2} \sin \left (2 \, f x + 2 \, e\right )}{4 \, f} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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